SOLUTION: Given log(base a)5 = 2.32, and log(base a)9=3.17, find log(base a) 25/9= amd find log(base a) radical 45 =
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Question 569126: Given log(base a)5 = 2.32, and log(base a)9=3.17, find log(base a) 25/9= amd find log(base a) radical 45 =
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Given log(base a)5 = 2.32, and log(base a)9=3.17, find log(base a) 25/9= amd find log(base a) radical 45 =
**
log(base a)=loga
loga(25/9)=loga(5^2/9)=2loga(5)-loga(9)=2*2.32-3.17=1.47
loga(√45)=loga(45^.5)=.5loga(45)=.5loga(5*9)=.5(loga(5)+loga(9))=.5(2.32+3.17)=2.745
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