SOLUTION: SOLVE. Log4(log3(log2 x))=0 the 4, 3, and 2 are bases

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Question 564552: SOLVE.
Log4(log3(log2 x))=0
the 4, 3, and 2 are bases
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Log4(log3(log2 x))=0
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log%284%2C%28log%283%2C%28log%282%2Cx%29%29%29%29%29+=+0
log%283%2C%28log%282%2Cx%29%29%29+=+1
log%282%2Cx%29+=+3
x = 8