SOLUTION: I need help solving for x in this logrithm: Log(11x + 9) = 3 + log(x + 3) First I moved both logs to the same side: Log(11x + 9) - log(x + 3) = 3 Then I divided the logs in

Question 563456: I need help solving for x in this logrithm:
Log(11x + 9) = 3 + log(x + 3)
First I moved both logs to the same side:
Log(11x + 9) - log(x + 3) = 3
Then I divided the logs in order to condense the equation:
Log (11x + 9)/(x + 3) = 3
Next I switched the equation from log form to expodential form:
10^3 = (11x + 9)/(x + 3)
Then I distributed the exponent to the 10 and multiplied (x + 3) to both sides:
1,000(x + 3) =(11x +9)
1,000x + 3,000 = 11x + 9
Then I put the x's on the same side & all whole numbers:
989x = -2991
Then I divided to find x:
X = -2991/989; x = -3.024266936.
Now I realize I did something wrong to come up with this answer so could you please help me?
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Assuming log is in base 10, your solution is correct. You want to make sure if the log is in base 10 or in base e (i.e. ln)
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