SOLUTION: how do you solve for x in terms of e or ln
in this example
{{{e^(2x)-2e^x-15=0}}}
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Question 560418: how do you solve for x in terms of e or ln
in this example
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
this is a quadratic in e^x ___ (e^x)^2 - 2(e^x) - 15 = 0
factoring ___ [(e^x) - 5][(e^x) + 3] = 0
e^x - 5 = 0 ___ e^x = 5 ___ x = Ln(5)
e^x + 3 = 0 ___ e^x = -3 ___ logarithms (natural or otherwise) are not defined for negative arguments
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