SOLUTION: 2log(2y)^2+log(2b)^2

SOLUTION: 2log(2y)^2+log(2b)^2

Algebra.Com

Question 553448: 2log(2y)^2+log(2b)^2
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2log(2y)^2+log(2b)^2
----
= 2log(4y^2) + 2log(2b)
----
= 2[log[4y^2*2b]]
----
= 2log[8y^2b]
--
= log[64y^4b^2]
=====================
Cheers,
Stan H.
RELATED QUESTIONS
log x+1/2log(x+2)=2 (answered by Alan3354)

2(Log a + Log b) � Log a � 2Log... (answered by Alan3354,josgarithmetic)

2log(x)-2 =... (answered by Alan3354)

2log(x+2)=log3+log(2x+1) (answered by nerdybill)

2log^3 2 log^3... (answered by Alan3354)

solve 2log X- log(X-2) =2 log... (answered by ikleyn)

2log(x+2)-log(x+5)=log2+log(x-2) (answered by solver91311)

solve log(7x^2+30x+2) - 2log(x+1) =... (answered by vleith)

2log(base 2) x=3+log(base 2) (x+16)? (answered by ewatrrr)