SOLUTION: how do i solve: log (base 2) 8^x = -3

Question 548913: how do i solve: log (base 2) 8^x = -3
Found 2 solutions by nerdybill, josmiceli:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
log (base 2) 8^x = -3
we can rewrite as:
log (base 2) (8)^x = -3
log (base 2) (2^3)^x = -3
log (base 2) 2^(3x) = -3
3x = -3
x = -1

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Get log base 2 on both sides of equation
Note that , so
, therefore

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