SOLUTION: express in a single log 3 loga (2x + 1) - 2 loga (2x - 1) + 2

Algebra.Com
Question 548804: express in a single log
3 loga (2x + 1) - 2 loga (2x - 1) + 2

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
express in a single log
3 loga (2x + 1) - 2 loga (2x - 1) + 2
-----
loga(2x+1)^3 - loga(2x-1)^2 + 2
----
= loga[(2x+1)^3/(2x-1)^2] +2
==============================
Cheers,
Stan H.

RELATED QUESTIONS

Express as a single logarithm. 3 loga (2x + 1) - 2 loga (2x - 1) + 2 A) logaa^2(2x (answered by stanbon)
express as equivalent expression that a single logarithm and if possible simplify ('a'... (answered by Fombitz)
Express the following as a single logarithm and simplify. • 3/4 loga x - 1/2 loga... (answered by Theo)
loga(x^2)-loga(x+1)=loga(x-3) (answered by mouk)
1) Express loga X2 + 2 loga Square root of X as a single logarithm. Simplify if possible. (answered by stanbon)
Simplify using at most a single logarithm:... (answered by Theo)
loga(2x+10)-loga(x^2-25) (answered by rapaljer)
Express as a single logarithum, and, if possible, simplify. 1/4 loga x + 6 loga y - 2... (answered by MathLover1)
Loga 1/25 =... (answered by Fombitz)