SOLUTION: log(x-9)=1-logx i do not just want the answer, i want steps on how to do it so i can apply it to my test

SOLUTION: log(x-9)=1-logx i do not just want the answer, i want steps on how to do it so i can apply it to my test

Algebra.Com

Question 546447: log(x-9)=1-logx
i do not just want the answer, i want steps on how to do it so i can apply it to my test
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
log(x-9)=1-logx
log(x-9)+logx=1
adddition in logs indicates multiplication in operations
log[(x-9)*x]=1
convert to exponential form: base(10) raised to log of number(1)=number[(x-9)*x]
10^1=[(x-9)*x]
x^2-9x-10=0
(x-10)(x+1)=0
x=-1 (reject, x>0)
or
x=10 (ans)
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