SOLUTION: log2(x + 2) + log2(x

SOLUTION: log2(x + 2) + log2(x - 4) = 4

Question 546006: log2(x + 2) + log2(x - 4) = 4
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
solve for x
log2(x + 2) + log2(x - 4) = 4
log2[(x+2)(x-4)]=4
change to exponential form: Base(2) raised to log of number(4)=number[(x+2)(x-4)]
..
2^4=(x+2)(x-4)
16=x^2-2x-8
x^2-2x-24=0
(x-6)(x+4)=0
x=6
or
x=-4 (reject, (x+2)>0)
RELATED QUESTIONS
Log2 (x+1) - Log2 X= Log2... (answered by htmentor)

Log2 (x+1) - Log2 X= Log2 4 (answered by Gentle Phill)

log2(x - 2) + 5 = 8 - log2... (answered by mukhopadhyay)

log2(x - 2) + 5 = 8 - log2... (answered by Nate)

log2(x - 2) + 5 = 8 - log2... (answered by jim_thompson5910)

log2(3x-2)-log2(x-5)=4 (answered by robertb)

log2(3x-2)+log2(x)=4 (answered by treeman101)

log2(x+6)+log2(2)=4 (answered by greenestamps,Boreal)

log2^x+log2^4=3 (answered by edjones)