SOLUTION: I need to Solve the equation log3 x^2 - log3(3x+18)=0 log is base 3 tried log3(x^2/3x+18)=0, not sure if this is right or how to proceed, also tried to remove log3 ended with

Question 542957: I need to Solve the equation log3 x^2 - log3(3x+18)=0
log is base 3 tried log3(x^2/3x+18)=0, not sure if this is right or how to proceed,
also tried to remove log3 ended with x^2-3x+18=0 removed 18from both sides x^2-3x=-18
tried to separate into to equations x=6, x=-3 neither fit into equation can not find another example in the book or in notes please help me figure out how to solve three of us and we still have no idea
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve the equation
log3 x^2 - log3(3x+18)=0
------------
log3[x^2/(3x+18)] = 0
x^2/(3x+18) = 3^0 = 1
----
x^2 = 3x+18
x^2-3x-18 = 0
---
Factor:
(x-6)(x+3) = 0
x = 6 or x = -3
====================
Cheers,
Stan H.

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