SOLUTION: solve equation log base 2 (X2-7x+14)=1 in this eqation, 2 is the base of log and 2 is the exponent for X

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Question 539104: solve equation
log base 2 (X2-7x+14)=1 in this eqation, 2 is the base of log and 2 is the exponent for X

Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!
log base 2 (x^2-7x+14)=1
(x^2-7x+14)=2^1
x^2-7x+14 = 2
x^2-7x+12 = 0
(x-4)(x-3) = 0
x = {3, 4}

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