SOLUTION: what is the solution of logarithm logx+log(x+1)=2log(1-x)

Question 536151: what is the solution of logarithm logx+log(x+1)=2log(1-x)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
what is the solution of logarithm logx+log(x+1)=2log(1-x)
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logx+log(x+1)=2log(1-x)
logx+log(x+1)-2log(1-x)=0
place under single log
log[(x(x+1))/((1-x)^2)]=0
convert to exponential form: base(10) raised to log of number(0)=number(x(x+1))/((1-x)^2)
10^0=1=(x(x+1))/((1-x)^2)
x(x+1)=(1-x)^2
x^2+x=1-2x+x^2
3x=1
x=1/3
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