SOLUTION: Hi, I have another hard one. Find the domain of the logarithmic function: f(x)=ln(1/x+3)

Question 535370: Hi, I have another hard one.
Find the domain of the logarithmic function:
f(x)=ln(1/x+3)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Hi, I have another hard one.
Find the domain of the logarithmic function:
f(x)=ln(1/(x+3))
**
x+3>0
x>-3
so you have an asymptote at x=-3
At x=2
ln(1/(x-3))=ln(1/1)=ln(1)=0
so it crosses the x-axis at x=2, and f(x) gradually becomes increasingly negative as x approaches infinity:
Domain: (-3,∞)
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