SOLUTION: How do I approach, and solve, this problem?:
2^logX + 3^logY = 2^log(X+1) + 3^log(Y+1)
Solve for X
Algebra.Com
Question 5299: How do I approach, and solve, this problem?:
2^logX + 3^logY = 2^log(X+1) + 3^log(Y+1)
Solve for X
Answer by arunpaul(104) (Show Source): You can put this solution on YOUR website!
here two unknown how can one equation can solve the x value
so please confarm the question there may be some wrong in this question
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