SOLUTION: log[2](log[2](log[3](2x-1)))=1

Question 527528: log[2](log[2](log[3](2x-1)))=1
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
I'll assume the number in [] represents log base...
log[2](log[2](log[3](2x-1)))=1
log[2](log[3](2x-1))=2^1
log[2](log[3](2x-1))=2
log[3](2x-1)=2^2
log[3](2x-1)=4
(2x-1)=3^4
2x-1=81
2x=82
x = 41

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