SOLUTION: Can you please help me figure out how to solve this problem? log(40x+200)=3 Here is what I came up with. log40x+log200=3 log40x+2.301=3 log40x=.699 x=.4363 When I plug X ba

Algebra.Com
Question 526762: Can you please help me figure out how to solve this problem?
log(40x+200)=3
Here is what I came up with.
log40x+log200=3
log40x+2.301=3
log40x=.699
x=.4363
When I plug X back into the equation, it doesn't come out right.

Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
It's not surprising that it doesn't come out right!
Because:
is not equal to
Here's what you must do:
Change this to the exponential form:If then
----> Simplify:
Subtract 200 from both sides.
Divide both sides by 40.


RELATED QUESTIONS

Please show how you got the answer. Question Solve for y: x=-3y+1 the book is showing (answered by Alan3354)
can you show me how to solve the problem -3(x-4)=-4x I came up with -3x+12=-4x and now... (answered by MathLover1)
Problem is:(3y/x^4)^-3... I can not figure out how they came up with the answer of... (answered by rapaljer)
I'm about to go crazy over here trying to figure out this problem!!! Can you PLEASE tell... (answered by askmemath)
I cannot figure out how to set up and solve this word problem. PLEASE HELP!!!! Here is (answered by nerdybill,stanbon)
Using the common or natural log to solve the exponnential equation symboliccally.... (answered by ankor@dixie-net.com,MathTherapy)
log[3](27)/log[3](9)= 27/9 I know that this is a true statement and the answer equals 3 (answered by Alan3354)
Hi, I am really struggling with this word problem involving consecutive integers, I have... (answered by josmiceli)
Please help me with this problem. I need to evaluate ∣ 4 ∣ + ∣-3... (answered by jim_thompson5910)