SOLUTION: How do I solve for the variable {{{ log (x+4) + log (x) = 9 }}}
Algebra.Com
Question 526672: How do I solve for the variable
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log (x+4) + log (x) = 9
-----
log[x(x+4)] = 9
---
x^2+4x = 10^9
---
x^2 + 4x - 10^9 = 0
----
It's pretty difficult to solve that for "x".
Did you post everything correctly?
-----
Cheers,
Stan H.
RELATED QUESTIONS
How do I solve the following for x?
log(base2)9 / log(base2)3 = log(base2)2x
I tried... (answered by lwsshak3)
Log base 9 of 3 to the 3x-4=x. How do I solve for... (answered by MathLover1)
log(6)^x+log(6)^(x-9)=2
How do I solve for x?
please... (answered by nerdybill)
How do I solve this simultaneous logarithm.
log (x-4)+ 2 log y = log 16
log x + log y = (answered by stanbon)
how do I solve the equation:... (answered by richard1234)
How do I solve these problems?
1. log(2 - x) = 0.5
2. log(x + 25) = log(x + 10) + (answered by Theo)
Solve for x to the nearest hundredth
2^x = 3/16
2^(x+4) = 3
x+4 = {{{ log( 2, 3 )... (answered by josgarithmetic)
How do i solve for x the question is log base 6(3x)-log base 6 to the 4=log base 6 to the (answered by lwsshak3)
how do you solve 9 log 10... (answered by lwsshak3)