SOLUTION: 2log x < log(x2-1)
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Question 518114: 2log x < log(x2-1)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ <\ \log(x^2\ -\ 1))
Use
\ =\ n\log_b(x))
To write
\ <\ \log(x^2\ -\ 1))
Use
\ <\ \log_b(\omega_2)\ \Leftrightarrow\ \omega_1\ <\ \omega_2)
(Because \ =\ \frac{\log_b(e)}{\omega})
is positive for all 
which is the domain of 
, is increasing over its entire domain.)
To write
Add 
to both sides:
Which is absurd. The solution set is the empty set.
John
My calculator said it, I believe it, that settles it
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