SOLUTION: log(base 16) x + log(base 4 x + log(base 2) x = 7
the answer is 16, but i want to know how they got it because i keep getting 16^1/3
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Question 516126: log(base 16) x + log(base 4 x + log(base 2) x = 7
the answer is 16, but i want to know how they got it because i keep getting 16^1/3
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
16 = 2^4 ___ log2(x) = 4[log16(x)]
16 = 4^2 ___ log4(x) = 2[log16(x)]
log16(x) + 2[log16(x)] + 4[log16(x)] = 7
7[log16(x)] = 7
log16(x) = 1
x = 16
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