SOLUTION: How would I solve this logarithmic equation loga(x) + loga (x-2)= loga (x+4)

SOLUTION: How would I solve this logarithmic equation loga(x) + loga (x-2)= loga (x+4)

Algebra.Com

Question 510308: How would I solve this logarithmic equation
loga(x) + loga (x-2)= loga (x+4)
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
loga(x) + loga (x-2)= loga (x+4)
a^loga(x) * a^loga (x-2)= a^loga (x+4)
x(x-2)=x+4
x^2-2x-x-4=0
x^2-3x-4=0
(x-4)(x+1)=0
x=4
.
Ed

RELATED QUESTIONS
loga(x^2)-loga(x+1)=loga(x-3) (answered by mouk)

loga x +... (answered by Gogonati)

loga(2x+10)-loga(x^2-25) (answered by rapaljer)

Solve the equation: loga (3x + 5) - loga (x - 5) = loga 8 (answered by dabanfield)

2loga x + 4 loga... (answered by Alan3354)

PLEASE HELP ME SOLVE THIS PROBLEM; Given that LOGa (x)=3.58 and LOGa (y) = 4.79, find... (answered by rapaljer)

1/2 loga (X+2)+ 1/2 loga(X-1)= 2/3 loga 27 (answered by stanbon)

Hi, I'm tried to solve these problems but I'm having trouble: 1) If loga(x) = 0.6 and... (answered by josgarithmetic,MathTherapy)

proof Loga... (answered by stanbon)