# SOLUTION: log base 3 (10x^2-x-2)=2+2*log base 3X solve for x I tried to change the 2*log base 3x into log base 3x^2. Then I think i should try and get the 2 left on the right side of the

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: log base 3 (10x^2-x-2)=2+2*log base 3X solve for x I tried to change the 2*log base 3x into log base 3x^2. Then I think i should try and get the 2 left on the right side of the       Log On

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 Click here to see ALL problems on logarithm Question 504499: log base 3 (10x^2-x-2)=2+2*log base 3X solve for x I tried to change the 2*log base 3x into log base 3x^2. Then I think i should try and get the 2 left on the right side of the equation to be a log base 3 to allow the log base 3 to cancel completely out. but I am not sure how to change 2 to a log base 3 if that is the correct step. Any help would be great. Thank you.Answer by stanbon(57228)   (Show Source): You can put this solution on YOUR website!log base 3 (10x^2-x-2)=2+2*log base3(X) solve for x ---------------------- log3(10x^2-x-2) - 2log3(x) = 2 --- log3(10x^2-x-2) - log3(x^2) = 2 --- log3[(10x^2-x-2/x^2] = 2 ---- (10x^2-x-2/x^2) = 9 --- 10x^2-x-2 = 9x^2 --- x^2-x-2 = 0 Factor: (x-2)(x+1) = 0 Positive solution: x = 2 =================== Cheers, Stan H. ===================