SOLUTION: Can anyone help me solve this log problem: Solve log(lower a) (8x+5)=log(lower a)(4x+29)
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Question 50391
:
Can anyone help me solve this log problem:
Solve log(lower a) (8x+5)=log(lower a)(4x+29)
Answer by
stanbon(48535)
(
Show Source
):
You can
put this solution on YOUR website!
log(lower a) (8x+5)=log(lower a)(4x+29)
Since the log to the base "a" are the same the numbers must be the same, so:
8x+5=4x+29
4x=25
x=6 1/4
Cheers,
Stan H.