SOLUTION: log4x+log4(x+12)=3 (x)(x+12)=4^3 x^2+4x+12=48 x^2+4x=36 x(x+12)=36 x=? I'm missing something right?

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Question 50122: log4x+log4(x+12)=3
(x)(x+12)=4^3
x^2+4x+12=48
x^2+4x=36
x(x+12)=36
x=?
I'm missing something right?
Answer by stanbon(48535) About Me  (Show Source):
You can put this solution on YOUR website!
log4x+log4(x+12)=3
(x)(x+12)=4^3
x^2+12x-64=0
(x+16)(x-4)=0
x=4
Cheers,
Stan H.