SOLUTION: How do I use logarithms to solve
10(1.07^5x+1)=12
Algebra.Com
Question 496228: How do I use logarithms to solve
10(1.07^5x+1)=12
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
How do I use logarithms to solve
10(1.07^(5x+1)=12
(1.07^(5x+1)=12/10=1.2
take log of both sides
(5x+1)log(1.07)=log(1.2)
5x+1=log1.2/log1.07=2.6947
5x=2.6947-1=1.6947
x=1.6947/5=.3389
Check:
10(1.07^(5x+1)
10(1.07^(2.6947)=10*1.2=12
RELATED QUESTIONS
how do i solve (3y-1)^6=80 using... (answered by lwsshak3)
use logarithms to solve each equation:
3(superscript x)= 5(superscript... (answered by Theo)
Use common logarithms to solve... (answered by savvyhush23)
Hi, i am in year 12 maths B and don't understand how to use logarithms at all. An example (answered by Alan3354)
how do I solve this Ln(e^19x^20) use to the properties of logarithms to... (answered by MathLover1)
How do you solve 2y=5x-1 and x=y+2? (Solve by graphing)
How do you solve x=5 and... (answered by Alan3354)
How do you solve y=1/5x-4? I am having trouble determing the numbers I should use to... (answered by solver91311)
It's a absolute value equation .. How do I solve --> |x-1| = 5x +... (answered by rothauserc)
How do I solve... (answered by MathLover1)