SOLUTION: Solve for x: log(4x^2)-log(16x)=1
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Question 49208: Solve for x: log(4x^2)-log(16x)=1
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
Assuming the log is base 10, then to remove the log we next to raise both sides to the base 10:
this is where the algebraic method and logs seem to me to be at odds to each other. Looking at the above line, we could do one of 2 approaches. Either divide the lefthand side first or move the 16x up to the righthand side.
Approach1:
Approach2:
so either x=0 or x-40=0
--> x=0 or x=40
This second approach seems to give us 2 answers whereas the first gave us just 1. However, putting x=0 into the original will give you an error, so the only solution is x=40... you must remember to check by substituting your answers back into the question, just to check.
jon.
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