SOLUTION: what's the answer to this, can i also have the solution so i could know how to do it...we are ask to find the value... 1. log2 8/ log2 32 = 2. log3 81/ log3 9 = 3. log 1000 /

Question 488191: what's the answer to this, can i also have the solution so i could know how to do it...we are ask to find the value...
1. log2 8/ log2 32 =
2. log3 81/ log3 9 =
3. log 1000 / log 0.01 =
4. log 8 + log3 - log 6 =
5. log 14 - log 2 =
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the value
1. log2 8/ log2 32
log2(2^3)/log2(2^5)
3log2(2)/5log2(2)=3/5
..
2. log3 81/ log3 9
log3(9^2)/log3(9)
2log3(9)/log3(9)=2
..
3. log 1000 / log 0.01
log(10^3)/log(10^-2)
3log(10)/-2log(10)=-3/2
..
4. log 8 + log3 - log 6
using calculator
log(8*3/6)=log (12)=1.0792
..
5. log 14 - log 2
using calculator
log(14/2)=log7=0.8415
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