SOLUTION: Just wondering if someone could explain how to solve to find x: 2 × (0.1)^x+1 = 25 thanking you Tracey

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Question 487661: Just wondering if someone could explain how to solve to find x:
2 × (0.1)^x+1 = 25
thanking you
Tracey
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
ust wondering if someone could explain how to solve to find x:
2 × (0.1)^x+1 = 25
**
2 × (0.1)^x+1 = 25
2*(0.1)^x=25-1=24
(0.1)^x=24/2=12
take log of both sides
xlog(0.1)=log12
x=log12/log(0.1)
x=1.0792/-1
x=-1.0792