SOLUTION: 3/2log 9/25 - 5log 2/3 + 2log 2/8, all in base 10
Algebra.Com
Question 483319: 3/2log 9/25 - 5log 2/3 + 2log 2/8, all in base 10
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
3/2log 9/25 - 5log 2/3 + 2log 2/8, all in base 10
**
3/2log 9/25 - 5log 2/3 + 2log 2/8
place under a single log
log[(9/25)^(3/2)*(2/8)^2/(2/3)^5]
log[(27/125)*(1/16)/(32/243)]
log[.1025]=-0.9893
RELATED QUESTIONS
Pls help in solving:{{{ (3/2)log base 10^(9/25)-5log base10^(3/2) 2log base... (answered by Alan3354)
Pls help in solving:{{{ (3/2)log base 10^(9/25)-5log base10^(3/2) + 2log base... (answered by Alan3354,ikleyn)
2log[base 3](x+4)-log[base... (answered by ewatrrr,stanbon)
Write the following as single logarithm:
1) 3log(x-1)-2log(x)+5log(x^2)-log(x+1)
2)... (answered by Edwin McCravy)
2log based 3 (x+4)- log base 3... (answered by stanbon)
rewrite the following expression as a single logarithm... (answered by lwsshak3)
express logx^2+5log(x-2)-1/2log(y+3)-log3 as a single... (answered by lwsshak3)
2log(base 2) x=3+log(base 2) (x+16)?
(answered by ewatrrr)
2log base 2 (c) + (log base 2 (a))÷... (answered by josgarithmetic)