SOLUTION: My pharmacology book gives the following equation for drug concentration at time t, C(t):
C(t) = C(0)exp(-CL/V)t
Taking logarithms, the authors arrive at:
lnC(t) = lnC
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-> SOLUTION: My pharmacology book gives the following equation for drug concentration at time t, C(t):
C(t) = C(0)exp(-CL/V)t
Taking logarithms, the authors arrive at:
lnC(t) = lnC
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Question 483069: My pharmacology book gives the following equation for drug concentration at time t, C(t):
C(t) = C(0)exp(-CL/V)t
Taking logarithms, the authors arrive at:
lnC(t) = lnC(0) - (-CL/V)t
Wouldn't it be PLUS (-CL/V)t, since C(0) is multiplied with e^(-CL/V)t ? Found 2 solutions by Alan3354, solver91311:Answer by Alan3354(69443) (Show Source):
