SOLUTION: My pharmacology book gives the following equation for drug concentration at time t, C(t):
C(t) = C(0)exp(-CL/V)t
Taking logarithms, the authors arrive at:
lnC(t) = lnC
Algebra.Com
Question 483069: My pharmacology book gives the following equation for drug concentration at time t, C(t):
C(t) = C(0)exp(-CL/V)t
Taking logarithms, the authors arrive at:
lnC(t) = lnC(0) - (-CL/V)t
Wouldn't it be PLUS (-CL/V)t, since C(0) is multiplied with e^(-CL/V)t ?
Found 2 solutions by Alan3354, solver91311:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
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The exponent is negative.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Either that or \right)\ =\ \ln\left(C_o\right)\ -\ \left(\frac{CL}{V}\right)t)
John
My calculator said it, I believe it, that settles it
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