SOLUTION: log4 4^0.8=x b^x=y 4^x=4^0.8 x=√4^0.8 x=1.74 but when changing 4^1.74=11.16 and 4^.8=3.03 I can't seem to be doing this right since the exponents do not match the value.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: log4 4^0.8=x b^x=y 4^x=4^0.8 x=√4^0.8 x=1.74 but when changing 4^1.74=11.16 and 4^.8=3.03 I can't seem to be doing this right since the exponents do not match the value.      Log On


   



Question 479051: log4 4^0.8=x
b^x=y
4^x=4^0.8
x=√4^0.8
x=1.74
but when changing 4^1.74=11.16 and 4^.8=3.03 I can't seem to be doing this right since the exponents do not match the value. please help

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
log4 4^0.8=x
b^x=y
4^x=4^0.8
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If you mean log%284%2C4%5E0.8%29+=+x
then x = 0.8
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