SOLUTION: Hi, I tried to solve 5^logx=50-x^log5 in the following manner Re- aligning the equation 5^logx+x^log5 =50 Taking log both sides logx X log5 + logx X log5=log50 log(x+5) + l

Question 478711: Hi,
I tried to solve 5^logx=50-x^log5 in the following manner
Re- aligning the equation
5^logx+x^log5 =50
Taking log both sides
logx X log5 + logx X log5=log50
log(x+5) + log(x+5)=log50
From here am having confusion
1.
log(x+5)(x+5)=log50
log(x+5)^2=log50
(x+5)^2=50=>x=(50)^1/2-(5) (or)
2.
log(x+5) + log(x+5)=log50
2log(x+5)=log50
2(x+5)=50
x+5=25
x=20
Which is correct?
Thanks and regards,
AN
Answer by Tatiana_Stebko(1539) (Show Source): You can put this solution on YOUR website!
I am sorry, but all incorrect
Your error - you incorrect use formula

Let
then Formula , so
or we can write it in this way , then
So
Substitute in equation

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