SOLUTION: log4x+log4(x-6)=2

Question 478615: log4x+log4(x-6)=2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
log4x+log4(x-6)=2
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log4x+log4(x-6)=2
place under single log using multiplication rule
log4(x(x-6))=2
convert to exponential form:(base(4) raised to log of number(2)=number(x(x-6)
4^2=x(x-6)
16=x^2-6x
x^2-6x-16=0
(x-8)(x+2)=0
x=8
or
x=-2 (reject, x>0)
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