# SOLUTION: solve for x log3 + log(x+4) = log5 + log(x-3)

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 Question 476522: solve for x log3 + log(x+4) = log5 + log(x-3)Answer by lwsshak3(6522)   (Show Source): You can put this solution on YOUR website!solve for x log3 + log(x+4) = log5 + log(x-3) ** log3 + log(x+4) = log5 + log(x-3) log3 + log(x+4) - log5 - log(x-3)=0 log3 + log(x+4) - (log5 + log(x-3))=0 place under a single log log(3*(x+4))/(5*(x-3)=0 convert to exponential form: (base(10) raised to log of number(0)=number(3*(x+4))/(5*(x-3) 10^0=3x+12/5x-15=1 3x+12=5x-15 2x=27 x=27/2=13.5 Check: log3 + log(x+4) = log5 + log(x-3) log3 + log(17.5) = log5 + log(10.5) 1.7202=1.7202