SOLUTION: i need help solving this and the steps logx-1=-log(x-9) and also log(1-x)+logx+log(x+4)

Question 474848: i need help solving this and the steps logx-1=-log(x-9) and also
log(1-x)+logx+log(x+4)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
i need help solving this and the steps logx-1=-log(x-9) and also
log(1-x)+logx+log(x+4)
**
logx-1=-log(x-9)
logx-1+log(x-9)=1
logx+log(x-9)=1
log(x)(x-9)=1
convert to exponential form: (base(10) raised to log of number(1)=number(x(x+9))
10^1=(x)(x-9)=10
x^2-9x-10=0
(x-10)(x+1)=0
x=10
or
x=-1 (reject, x-9>0)
..
log(1-x)+logx+log(x+4)
log(1-x)(x)(x+4)
We need an equation to come up with a solution
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