SOLUTION: solve 2log3 +log2x = log(3x+1) Evaluate 2logbase2 4 +3logbase2 5 -log-log2 25-log2 10

Question 474675: solve 2log3 +log2x = log(3x+1)
Evaluate 2logbase2 4 +3logbase2 5 -log-log2 25-log2 10
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve
2log3 +log2x = log(3x+1)
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log(3^2) + log(2x) = log(3x+1)
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log[9*2x] = log(3x+1)
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18x = 3x+1
15x = 1
x = 1/15
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Evaluate 2log2(4) +3log2(5) -log-log2 25-log2 10
This post is undecipherable.
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Cheers,
Stan H.
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