SOLUTION: (log16+2log2)/log4=x

Question 471118: (log16+2log2)/log4=x
Found 3 solutions by nerdybill, Alan3354, bucky:
Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!
(log16+2log2)/log4=x
(log16+log2^2)/log4=x
(log16+log4)/log4=x
(log16+log4)-log4=x
log16=x
1.204 = x

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
(log16+2log2)/log4=x
(log16+log4)/log4=x
log(64)/log(4) = x
x = 3

Answer by bucky(2189)   (Show Source): You can put this solution on YOUR website!
Another way of working this problem:
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Convert 16 to 2^4 and 4 to 2^2
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Bring the exponents out as multipliers of the logarithm terms
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Since both terms in the numerator involve log 2, the terms can be added together.
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The log 2 in the numerator cancels with the log 2 in the denominator and you are left with:
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Which reduces to x = 3

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