SOLUTION: log2(x) + log2(8) = log2(64 − x) + 3 Solve for x

Algebra.Com
Question 470124: log2(x) + log2(8) = log2(64 − x) + 3
Solve for x

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
log2(x) + log2(8) = log2(64 − x) + 3
Solve for x
--------------------
log2(x) + 3 = log2(64-x) = 3
----
log2(x) = log2(64-x)
---
x = 64-x
2x = 64
x = 32
===============
Cheers,
Stan H.
======================

RELATED QUESTIONS

Solve the logarithmic equation for x. log2 3 + log2 x = log2 5 + log2(x − 2) x = (answered by lwsshak3)
Log2 (x+2) = log2 3-log2... (answered by Alan3354,MathTherapy)
Solve the equation. 2 log2(x) − log2(x - 3) = 2 +... (answered by Earlsdon)
solve log2 5 + 3 log2 x=3 (answered by nerdybill)
Solve: Log2(2) +log2(x+3)=5 (answered by stanbon)
solve for x log2 x + log2... (answered by jsmallt9)
log2^x+log2^4=3 (answered by edjones)
log2^x = log2^5... (answered by themathtutor2009)
log2 7x + log2 x =... (answered by ccs2011,Tatiana_Stebko)