SOLUTION: log(x+4)=log4+logx
Algebra.Com
Question 469716: log(x+4)=log4+logx
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
log(x+4)=log4+logx
log(x+4)=log(4x)
x + 4 = 4x
3x = 4
x = 4/3
--------
RELATED QUESTIONS
log(x+4)=logx+log4 (answered by Alan3354)
How do I solve the following problem: logx-log3=log4-log(x+4). (answered by sdmmadam@yahoo.com)
Evaluate log(X^logX) =... (answered by stanbon)
Logx+log... (answered by josgarithmetic)
log(x+3)+log(x+4)=log(X3+13x2)-logx (answered by ikleyn)
4 logx - 6 log... (answered by stanbon)
(log4(log4^x))=-4 (answered by jsmallt9)
2 log(x+2)+log4 = log x + 4... (answered by longjonsilver)
Solve logarithmic equation
Log(x+10)-log(x+4)=logx (answered by ewatrrr)