Hi,

log4[x]+log4[x-63]=3

log4[x(x-63)] = 3



 4^3 = x(x-63)

  x^2 -63x - 64 = 0

factoring:

 (x-64)(x+1) = 0

  (x-64)= 0  x = 64

  (x+1) = 0  x = -1 Extraneous solution

  64 is the real solutions for x 

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