SOLUTION: Prove that log 3=(log 2)+ (1/2)-(1/8)+(1/24)-(1/64)+....and so on.
Algebra.Com
Question 464432: Prove that log 3=(log 2)+ (1/2)-(1/8)+(1/24)-(1/64)+....and so on.
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
This is true if and only if
,
because it will satisfy the logarithm identity
. However, the above series is equal to ln 3/2. If you know the Taylor series for ln x centered at 1
We can replace x = 3/2 and get a true result. Hence the original equation is true.
RELATED QUESTIONS
1/2=log[64](8) (answered by edjones)
log 1/2 8 =... (answered by Alan3354)
Prove that
log(1+2+3)= log1+... (answered by Alan3354,josmiceli)
if a^2+b^2=7ab,prove that log 1/3(a+b)=1/2[log a+log... (answered by CharlesG2)
If a^2+b^2=7ab,prove that log{1/3(a+b)}=1/2(log a + log b)
(answered by ikleyn)
prove that : log 3 of base 2 multiply log 2 of base 3 = 1 (answered by Theo)
log(x + y) = log 3 + 1/2 log x + 1/2 log y
prove x^2 + y^2 = 7xy
(answered by MathLover1)
Solve the following:
log(7)24−log7(x+5)=log(7)8... (answered by harpazo)
If log (x+y)/2 = 1/2 (log x + log y) prove that x =... (answered by ikleyn)