SOLUTION: Solve log base 2 (x)+ log base 2 (2x+1)=0

Question 457945: Solve log base 2 (x)+ log base 2 (2x+1)=0
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!

==>
==>
==>
==> (2x-1)(x+1) = 0 ==> x = 1/2, -1.
Reject x = -1 (will not satisfy the original equation).
Hence the final answer is x = 1/2.
RELATED QUESTIONS
0= log base 5 (x-2) - log base 5... (answered by MathLover1)

how do you solve log base 4 (log base 3 (log base 2 of X)) = 0?? (answered by stanbon)

solve 1/2 log 25 base 6 + log x base 6 = log 20 base... (answered by solver91311,lwsshak3)

solve for x: Log base 10(log base 2(log base4 x))=... (answered by lwsshak3)

Solve for x: (A.) (5/2) log(base 4)4 = log(base 4)(2x-3) (B.) Log(base 3)(x+2)-... (answered by stanbon)

solve log(base 9)(2x+1) - log(base 3)(x-1) =... (answered by MathLover1)

Please help me solve this question Log 2 base x multiplied by log 2 base 2x = log 2 base (answered by stanbon)

Please help me solve this simultaneous equation: log x base 3 = y = log (2x-1) base 9 (answered by Edwin McCravy)

log base 2 (7x+1)=log base 2... (answered by jsmallt9)