# SOLUTION: Solve: logbase3(logbasex(logbase4 16)) = 1 Solve: 6^2logbase6 X + logbase6 X =125 Write the expression as a single logarithm: 3loga - logb - (1/2)logc

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Solve: logbase3(logbasex(logbase4 16)) = 1 Solve: 6^2logbase6 X + logbase6 X =125 Write the expression as a single logarithm: 3loga - logb - (1/2)logc      Log On

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 Click here to see ALL problems on logarithm Question 456781: Solve: logbase3(logbasex(logbase4 16)) = 1 Solve: 6^2logbase6 X + logbase6 X =125 Write the expression as a single logarithm: 3loga - logb - (1/2)logcAnswer by stanbon(57361)   (Show Source): You can put this solution on YOUR website! Solve: logbase3(logbasex(logbase4 16)) = 1 ---- log3(logx(2)) = 1 --- logx(2) = 3 --- x^3 = 2 x = 2^(1/3) =============== Solve: 6^2logbase6 X + logbase6 X =125 36*log6(x)) + log6(x) = 125 --- 37log6(x) = 125 --- x^37 = 6^125 --- x = 425.49 ====================== Write the expression as a single logarithm: 3loga - logb - (1/2)logc --- loga^3 - logb - logc^(1/2) --- = log[a^3/(bc^(1/2))] ============================ Cheers, Stan H.