SOLUTION: I need to know how to get the log for the following equation:
478 = 18.5(10^x)
I keep getting 2.11449, but the correct answer is 1.4123
I need to know what I am doing wron
Algebra.Com
Question 455028: I need to know how to get the log for the following equation:
478 = 18.5(10^x)
I keep getting 2.11449, but the correct answer is 1.4123
I need to know what I am doing wrong. Thanks for your help!
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
I need to know how to get the log for the following equation:
478 = 18.5(10^x)
478/18.5=10^x
take log of both sides
log(478/18.5)=log(10^x)=x (log of base raised to x=x)
by calculator
x=log(478/18.5)=1.4123
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