SOLUTION: how do i evaluate log(base 3)1/3 + log(base 5) square root 5

Question 454172: how do i evaluate
log(base 3)1/3 + log(base 5) square root 5
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
how do i evaluate
log(base 3)1/3 + log(base 5) square root 5
..
log3(1/3)+log5(5^1/2)
convert to exponential form:(base raised to log of number(x)=number
3^x=1/3
3^-1=1/3
x=-1(log of 1/3, base3)
check:3^x=3^-1=1/3
..
log5(5^1/2)
5^x=5^1/2
5^1/2=5^1/2
x=1/2(log of 5^1/2, base5)
check:
5^x=5^1/2
..
ans:
log3(1/3)+log5(5^1/2)
-1+1/2=-1/2
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