SOLUTION: Determine the positive root of the following equation: log3(c - 4) + log3(c + 6) = 4. (Please round your answer to one decimal place.) Answer

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Question 453069: Determine the positive root of the following equation:
log3(c - 4) + log3(c + 6) = 4.

(Please round your answer to one decimal place.)

Answer

Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!
log3(c - 4) + log3(c + 6) = 4
log3(c - 4)(c + 6) = 4
(c - 4)(c + 6) = 3^4
c^2 + 6c - 4c -24 = 81
c^2 + 2c -105 = 0
apply the quadratic formula to find the roots:
c = {9.3, -11.3}
throw out the negative root leaving:
c = 9.3
.
details of quadratic to follow:
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=424 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 9.295630140987, -11.295630140987. Here's your graph:





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