SOLUTION: Change to exponential form
log 10^x + log 10 (x + 15) = 2
{{{log (10, x) + log (10, (x+15)) = 2}}}
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Question 4506: Change to exponential form
log 10^x + log 10 (x + 15) = 2
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
By the first law of logarithms, log M + log N = log MN
Convert from logarithmic notation to exponential form by writing this as
Set equal to zero:
Factor the trinomial:
Therefore x = -20 or x = 5.
However, if x = -20, then the original equation results in log (-20) + log (-5) which is not a real number, so this answer must be rejected.
Final answer is x = 5 the only possible solution.
R^2 at SCC
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