SOLUTION: Solve the logarithmic equation. Be sure to reject any value of x that produces the logarithmic of a negative number or the logarithm of 0. {{{log(3,x)+log(3) (4x-9)=2}}} [The

Question 450523: Solve the logarithmic equation. Be sure to reject any value of x that produces the logarithmic of a negative number or the logarithm of 0.

[The 3 next to the second log is suppose to be a base.]
Type an integer or a fraction. Simplify your answer. Use a comma to seperate answers if necessary.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
log(3,x)+log(3) (4x-9)=2
3^log(3,x)+3^log(3) (4x-9)=3^2
x(4x-9)=9
4x^2-9x-9=0
(x-3)(4x+3)=0
x=3
.
Ed
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