SOLUTION: log(4-3x)-log145=-2

Question 448123: log(4-3x)-log145=-2
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
Since log(a/b) = log a - log b, we can combine the logs on the LHS of the equation:
log(4-3x)-log145=-2
log((4-3x)/145) = -2
To "undo" the log, perform the inverse operation:
10^log((4-3x)/145) = 10^(-2)
(4-3x)/145 = 0.01
Solving for x gives:
4-3x = 1.45
x = 0.85
Check:
log(4-3*0.85) - log 145 = log 1.45 - log 145 = -2
RELATED QUESTIONS
log(2) 3x = log(2) 10 =... (answered by ikleyn)

log[4](3x+1)=2 (answered by jsmallt9)

Log 2 (3x-2)- Log 2... (answered by edjones)

Log 2 (3x-2)- Log 2... (answered by lwsshak3)

(log[2]3)+(log[2]x)=(log[2]5)+... (answered by Fombitz)

log base 2 (3x+2) -log base 4... (answered by stanbon)

Solve: log[8](3x+2)=4... (answered by jb007mi6)

log 3x= log 4+... (answered by solver91311)

Rewrite 2 log(5x) + 4 log(3x) - 2 log(45x) as one simplified... (answered by ewatrrr)