SOLUTION: x^3-5x^2+4x+6, 3 is a zero find all zeros

Question 444526: x^3-5x^2+4x+6, 3 is a zero find all zeros
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
x^3-5x^2+4x+6, 3 is a zero find all zeros
..
since 3 is a known zero, divide (x^3-5x^2+4x+6)/(x-3) either by long division or synthetic division.
You should get a quotient (x^2-2x-2). This won't factor nicely so you must use the quadratic formula to solve for the other 2 zeros.
a=1, b=-2, c=-2
x=[-(-2)+-sqrt((-2)^2-4*1*-2)]/2*1
x=[2+-sqrt(4+8)]/2
x=(2+-√12)/2
x=(2+-2√3)/2
x=1+-√3
x=2.732
or x=-.732
ans:
zeros are: -.732, 2.732, and 3
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